Editing Estimating power need of motor drive system
Your changes will be displayed to readers once an authorized user accepts them. (help) |
Warning: You are not logged in. Your IP address will be publicly visible if you make any edits. If you log in or create an account, your edits will be attributed to your username, along with other benefits.
The edit can be undone.
Please check the comparison below to verify that this is what you want to do, and then save the changes below to finish undoing the edit.
Latest revision | Your text | ||
Line 11: | Line 11: | ||
==Calculations== | ==Calculations== | ||
− | Instantenous | + | Instantenous power output of motor can be estimated from the equation: |
− | <math>P_{electrical} [W] = \frac{Torque [Nm] * Speed [RPM]}{0.095488*efficiency [%]}</math> | + | <math>P_{mechanical} [W] = \frac{Torque [Nm] * Speed [RPM]}{9.5488} </math> |
+ | |||
+ | As that is the ''output'' mechanical power of motor, the input electrical power should be estimated by: | ||
+ | |||
+ | <math>P_{electrical} [W] = \frac{P_{mechanical}}{0.01*efficiency [%]} = \frac{Torque [Nm] * Speed [RPM]}{0.095488*efficiency [%]}</math> | ||
Example: | Example: | ||
Line 28: | Line 32: | ||
{{tip|People tend generally to overestimate the power need. In most cases, required power supply wattage is significantly less than the combined power ratings of the motors in the system. This is the case if all motors are not running at their maximum speed and torque at the same moment.}} | {{tip|People tend generally to overestimate the power need. In most cases, required power supply wattage is significantly less than the combined power ratings of the motors in the system. This is the case if all motors are not running at their maximum speed and torque at the same moment.}} | ||
− | |||
− | |||
− | |||
− | |||
− |